∫-2u^2/(1-u^2)du
=∫(2-2u^2-2)/(1-u^2)du
=∫(2-2u^2)/(1-u^2)du-∫2/(1-u^2)du
=∫2du-∫[(1+u)+(1-u)]/(1-u^2)du
=∫2du-∫(1+u)/(1-u^2)+(1-u)/(1-u^2)du
=∫2du-∫1/(1-u)+1/(1+u)du
=∫2du-∫1/(1-u)du-∫l/(1+u)du
-2u²/(1-u²)=(2-2u²-2)/(1-u²)=2-2/(1-u²)=2- (1+u+1-u)/((1+u) (1-u)) =2-1/(1+u)-1/(1-u)
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