要使f(x)=lnx+2x2+mx+1在(0,+∞)内单调递增,则f'(x)≥0在(0,+∞)恒成立,即f'(x)= 1 x +4x+m≥0恒成立,∴m≥?( 1 x +4x)在(0,+∞)恒成立,∵当x>0时, 1 x +4x≥2 1 x ?4x =2 4 =4,∴?( 1 x +4x)≤?4,即m≥-4,∴p:m≥-4,∵q:m≥-5,∴p是q的充分不必要条件.故选:A.