一道大一高数题!求解答!

2024-11-07 21:35:17
推荐回答(1个)
回答1:

原式={75/[(5-x)*(x^2+5x+25)]-1/(5-x)}=[75-x^2-5x-25]/[(5-x)*(x^2+5x+25)]
=[x^2+5x-50]/[(x-5)*(x^2+5x+25)]=[(x-5)(x+10)]/[(x-5)*(x^2+5x+25)]
=(x+10)/(x^2+5x+25)
带入x=5,可得原式=15/75=1/5