y✀=(2y-x^2)⼀x的通解,用一阶线性非齐次方程来解

2025-01-20 06:00:28
推荐回答(1个)
回答1:

微分方程即 y' - (2/x)y = -x,
通解 y = e^(∫2dx/x) [∫-xe^(-∫2dx/x)dx + C]
= x^2[ -∫dx/x + C] = x^2(-lnx + C)