有原题可知，比数列{an}通项式an=a1*q^(n-1),所以bn = (a1 * a2 * a3 *...an)^(1/n) = (a1^n * q^(0+1+2+...n-1))^(1/n) = a1 * (q^(n(n+1)/2))^(1/n) = a1*q^((n-1)/2) = a1*P由于P不是常数，等比结论不成立？！
