sin2x=√3cos（3π/2-x）sin2x=-√3sinx2sinxcosx-√3sinx=0sinx（2cosx-√3）=0解得sinx=0过cosx=√3/2即x=kπ或x=π/6+2kπ或x=-π/6+2kπ，k∈Zx=kπ时，k=1,2,3满足题意x=π/6+2kπ时，k=1满足题意x=-π/6+2kπ时，k=1满足题意综上π，2π，3π，11π/6，13π/6满足题意
