求定积分∫上限2,下限1 dx ⼀ (根号下4-x^2),要过程?

2024-11-04 15:57:07
推荐回答(1个)
回答1:

令x=2sint 则dx=2costdt
当x=1时 t=π/6 当x=2时 t=π/2
原式=∫上限π/2,下限π/6 (2costdt)/2cost=∫上限π/2,下限π/6 dt=π/2-π/6=π/3