解:先考虑定义域x>0 1-x>0x+3>0再考虑函数单调性x<1-xx+3<1解上联立不等式组得：不等式无解。
log0.5x>log0.5(1-x)00 log2(x+3)<00-3
∵log0.5x>log0.5(1-x)∴0∴0∵log2(x+3)＜0∴ 0∴-3
