数据结构课程设计 二叉排序树的实现 用顺序和二叉链表作存储结构
推荐回答(2个)
/*以下是用c++ 实现的二叉信行排序树的含坦锋源代码*/
#include
typedef struct TreeNode
{
int key;
struct TreeNode *left;
struct TreeNode *right;
}treeNode;
class BiSortTree
{
public:
BiSortTree(void);
void desplayTree(void);//显示这个树
void insertTree(int key);//在树中插入一个值
deleteTree(int key);//在树中谈晌删除一个值
treeNode* searchTree(int key);//在树中查找一个值
~BiSortTree();
private:
treeNode* buildTree(treeNode* head,int number);//建立一个树
treeNode* search(treeNode* head ,int key);//查找
treeNode* BiSortTree::searchParent(treeNode* head,treeNode* p);//查找出p的父亲节点的指针
treeNode* BiSortTree::searchMinRight(treeNode* head);//找到右子树中最小的节点
void showTree(treeNode* head);//显示
void destroyTree(treeNode* head);//删除
treeNode *Head;
};
/**************以下是建立一个二叉排序树****************/
BiSortTree::BiSortTree()
{
cout<<"建立一棵二叉排序树,请输入你要建树的所有数(以-1 作为结束标志!): "< Head=NULL;
int number;
cin>>number;
while(number!=-1)
{
Head=buildTree(Head,number);
cin>>number;
}
}
treeNode* BiSortTree::buildTree(treeNode* head,int number)
{
treeNode *p;
p=new treeNode;
p->key=number;
p->left =p->right=NULL;
if(head==NULL)
{
return p;
}
else
{
if(p->key key)
head->left=buildTree(head->left,number);
else
head->right=buildTree(head->right,number);
return head;
}
}
/*****************以下是在一棵二叉排序树插入一个数***********************************/
void BiSortTree::insertTree(int key)
{
Head=buildTree(Head,key);
}
/*****************以下是在一个二叉排序树查找一个数是否存在*************************/
treeNode* BiSortTree::searchTree(int key)
{
return search(Head,key);
}
treeNode* BiSortTree::search(treeNode* head ,int key)
{
if(head==NULL)
return NULL;
if(head->key==key)
return head;
else
{
if(keykey )
return search( head->left,key);
else
return search(head->right,key);
}
}
/************以下是在一个二叉排序树删除一个给定的值*********************************/
BiSortTree::deleteTree(int key)
{
treeNode *p;
p=NULL;
p=search(Head,key);
if(p==NULL)
{
cout<<"Don't find the key";
}
if(p==Head)
{
Head=NULL;
}
else
{
treeNode* parent;
parent=searchParent(Head,p);
if(p->left==NULL&&p->right==NULL)//叶子节点
{
if(parent->left==p)
{
parent->left=NULL;
}
else
{
parent->right=NULL;
}
}
else//非叶子节点
{
if(p->right==NULL)//该节点没有右孩子
{
if(parent->left==p)
{
parent->left=p->left ;
}
else
{
parent->right=p->left;
}
}
else//该点有左右孩子
{
treeNode * rightMinSon,* secondParent;//secondParent为右子树中的最小节点的父亲
rightMinSon=searchMinRight(p->right);
secondParent=searchParent(p->right ,rightMinSon);
secondParent->left=rightMinSon->right;
if(p->right==rightMinSon)//右子树中的最小节点的父亲为p
{
p->right=rightMinSon->right ;
}
p->key=rightMinSon->key ;
}
}
}
}
treeNode* BiSortTree::searchParent(treeNode* head,treeNode* p)
{
if(head->left==p||head->right==p||head==p||head==NULL)
return head;
else
{
if(p->keykey)
return searchParent(head->left ,p);
else
return searchParent(head->right ,p);
}
}
treeNode* BiSortTree::searchMinRight(treeNode* head)//找到右子树中最小的节点
{
if(head->left ==NULL||head==NULL)
{
return head;
}
else
{
return searchMinRight(head->left);
}
}
/*****************以下是显示一个二叉排序树****************************************/
void BiSortTree::desplayTree(void)
{
showTree(Head);
cout<}
void BiSortTree::showTree(treeNode* Head)
{
if(Head!=NULL)
{
showTree(Head->left ) ;
cout<key<<' ' ;
showTree(Head->right) ;
}
}
/*****************以下是删除一棵整二叉排序树************************************/
BiSortTree::~BiSortTree()
{
cout<<"已经消除了一棵树!!!!"<destroyTree(Head);
}
void BiSortTree::destroyTree(treeNode* head )
{
if(head!=NULL)
{
destroyTree(head->left );
destroyTree(head->right );
delete head;
}
}
/*********************/
void print()
{
cout<<<"1.显示树"< <<"2.插入一个节点"<<<"3.寻找一个节点"<<<"4.删除一个节点"<}
void main()
{
BiSortTree tree;
int number;
int choiceNumber;
char flag;
while(1)
{
print() ;
cout<<"请选择你要进行的操作(1~4)"< cin>>choiceNumber;
switch(choiceNumber)
{
case 1:
tree.desplayTree();break;
case 2:
cout<<"请插入一个数: "< cin>>number;
tree.insertTree(number);
tree.desplayTree();
break;
case 3:
cout<<"请插入你要找数: "< cin>>number;
if(tree.searchTree(number)==NULL)
{
cout<<"没有发现"< }
else
{
cout<<"发现"<
}
break;
case 4:
cout<<"请输入你要删除的数: "< cin>>number;
tree.deleteTree(number);
tree.desplayTree();
break;
default: break;
}
cout<<"你是否要继续(Y/N)?"< cin>>flag;
if(flag=='N'||flag=='n')
break;}}这个是代码运行一下
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