半导体物理中证明空穴电导有效质量

2024-11-02 17:45:49
推荐回答(2个)
回答1:

σ = e^2*τ(ph+pl)/mcp* = e^2*τ(ph)/mph*+e^2*τ(pl)/mpl* ---(1)
ph = A(kt)3/2(mph*)3/2, pl = A(kt)3/2(mpl*)3/2 ---(2)

将(2)带入(1)式得:
1/mcp* = (mph*1/2+mpl*1/2)/(mph*3/2+mpl*3/2) ---(3)
由(3)得:
mcp* = (mph*3/2+mpl*3/2)/(mph*1/2+mpl*1/2)

回答2:

你确定你的题目是正确的?