y=xe^x^2的二阶导数怎样求

2024-11-10 10:15:45
推荐回答(2个)
回答1:

y = xe^(x²)
y' = e^(x²)+2x²e^x² = (1+2x²)e^x²
y'' = (1+2x²)' e^x² + (1+2x²)(e^x²)'
= 4xe^(x²) + (1+2x²)2xe^(x²)
= 2x(3+2x²) e^(x²)

回答2:

就按照乘法的导数去求啊