初3分式的题目

x^2-y^2/x+y - 4x(x-y)+y^2/2x-y
2025-04-13 08:01:07
推荐回答(2个)
回答1:

[x^2-y^2]/[x+y] -[ 4x(x-y)+y^2]/[2x-y]
=[(x+y)(x-y)]/[x+y]-[4x^2-4xy+y^2]/[2x-y]
=[x-y]-[2x-y]^2/[2x-y]
=x-y-[2x-y]
=-x

回答2:

楼主是要化简吧?
原式=x^2-y^2/2x - 4x^2+4xy
=- 3x^2+4xy-y^2/2x