∫上限3下限0(1+x^2)^(1⼀5)dx 用换元法求定积分

2025-01-20 17:08:33
推荐回答(1个)
回答1:

x³/(x²+1)
=(x³+x-x)/(x²+1)
=x-x/(x²+1)
所以原式=∫(0,5)xdx-∫(0,5)x/(x²+1)dx
=∫(0,5)xdx-1/2∫(0,5)d(x²+1)/(x²+1)
=x²/2-1/2*ln(x²+1) (0,5)
=25/2-ln√26