已知a=根号3 +1 b=根号3 -1,求(a^2+2ab+b^2)⼀(a^2 - b^2)

已知a=根号3 +1 b=根号3 -1,求(a^2+2ab+b^2)/(a^2 - b^2)
2024-11-21 21:15:19
推荐回答(2个)
回答1:

(a^2+2ab+b^2)/(a^2 - b^2)
=(a+b)²/[(a+b)(a-b)]
=(a+b)/(a-b)
当a=根号3 +1 b=根号3 -1时
原式=(√3+1+√3-1)/(√3+1-√3+1)
=2√3÷2
=√3

回答2:

原式=(a+b)²/(a+b)9a-b)
=(a+b)/(a-b)
=(√3+1+√3-1)/(√3+1-√3+1)
=2√3/2
=√3