函数f(x+1)的定义域为[-2,3],-2<=x<=3-1<=x+1<=4即函数f(x)的定义域是[-1,4]-1<=2x^2-2<=41/2<=x^2<=3x^2>=1/2得:x>=根号2/2或x<=-根号2/2x^2<=3得-根号3<=X<=根号3取交集得:根号2/2<=X<=根号3或-根号3<=X<=-根号2/2.以上即为定义域
