20022003*20032002-20022002*20032003的简便算法

要过程
2024-11-08 05:56:41
推荐回答(1个)
回答1:

20022003*20032002-20022002*20032003
=(20022002+1)*(20022002+10000)-20022002*(20022002+10001)
设20022002=n
原式=(n+1)*(n+10000)-n*(n+10001)
=n^2+10001n+10000-n^2-10001n
=10000