xcosx^2的不定积分怎么求

2024-12-03 20:49:35
推荐回答(2个)
回答1:

你好!用凑微分法∫xcos(x^2)dx=∫cos(x^2)d(x^2)=sin(x^2)+c。经济数学团队帮你解答,请及时采纳。谢谢!

回答2:

∫xcos(x²)dx
=(1/2)∫cos(x²)d(x²)
=(1/2)sin(x²)+C