(2x^2-x^2+2x+1)/2x^2=x+l2x^3+X^2-2x-1=02(x-1)^2*(x+1)+3(x^2-1)=0(x+1)(x-1)[2(x-1)+3]=0所以:x=1,x=-1,x=-0.5x不等于-1补充问题答案:(x+1)^2-2x^2=x(x+1) 2x^2-x-1=02(x-1)^2+3x-3=0 x=-0.5
