废水处理过程中!如果计算单个池子的废水反应停留时间?

2025-02-09 02:13:55
推荐回答(1个)
回答1:

  ①污水日处理流量为100m3/d, 系统进料泵的流量为12m3/d(单台), 加压泵的流量为12.5m3/d(单台),
因此,初步确定设计流量为12m3/h, 每天运行8小时。一级接触氧化池的有效容积是V1= 5.0×3.0×2.2=33m3,
水力停留时间为T1=2小时45分钟;二级接触氧化池的有效容积是V2=3.0×3.0×2.2=19.8m3,水力停留时间为T2=1小时40分钟;沉淀池的有效容积是V3=3.0×1.0×2.1=6.2m3水力停留时间为T3=30分钟;中间水池的有效容积是V4=3.0×2.0×2.1=12.6m3,水力停留时间为T4=1小时。

  ②污水处理过程根据微生物的需氧量,水中的溶解氧浓度应满足在2~3mg/L,
过高或过低会导致出水水质变差,DO过高容易引起污泥的过氧化,且浪费能源;过低时微生物得不到充足的DO,有机物分解不彻底。二级接触氧化池出口处氧浓度达到2mg/L为宜。

  ③水位控制:调节池低水位控制在0.5m,
高水位控制在2.10m;中间水池低水位控制在0.5m,高水位控制在2.0m;清水池低水位控制在0.5m,高水位控制在2.10m。

  ④反冲洗时间的确定:现场根据过滤罐压力的变化情况确定反冲洗时间。

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